Solve r:2x+4y-16=0

$$r : 2 x + 4 y - 16 = 0$$

Solve for r

$$\left\{\begin{matrix}r=-\frac{8\left(y-4\right)}{x}\text{, }&x\neq 0\\r\in \mathrm{R}\text{, }&y=4\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$rx+8y-32=0$$

Subtract 8y from both sides. Anything subtracted from zero gives its negation.

$$rx-32=-8y$$

Add 32 to both sides.

$$rx=-8y+32$$

The equation is in standard form.

$$xr=32-8y$$

Divide both sides by x.

$$\frac{xr}{x}=\frac{32-8y}{x}$$

Dividing by x undoes the multiplication by x.

$$r=\frac{32-8y}{x}$$

Divide -8y+32 by x.

$$r=\frac{8\left(4-y\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{8\left(y-4\right)}{r}\text{, }&r\neq 0\\x\in \mathrm{R}\text{, }&y=4\text{ and }r=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$rx+8y-32=0$$

Subtract 8y from both sides. Anything subtracted from zero gives its negation.

$$rx-32=-8y$$

Add 32 to both sides.

$$rx=-8y+32$$

The equation is in standard form.

$$rx=32-8y$$

Divide both sides by r.

$$\frac{rx}{r}=\frac{32-8y}{r}$$

Dividing by r undoes the multiplication by r.

$$x=\frac{32-8y}{r}$$

Divide -8y+32 by r.

$$x=\frac{8\left(4-y\right)}{r}$$