Solve for r
r=6\left(\sqrt{3}-1\right)\approx 4.392304845
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\left(1+\sqrt{3}\right)r=12
Combine all terms containing r.
\left(\sqrt{3}+1\right)r=12
The equation is in standard form.
\frac{\left(\sqrt{3}+1\right)r}{\sqrt{3}+1}=\frac{12}{\sqrt{3}+1}
Divide both sides by 1+\sqrt{3}.
r=\frac{12}{\sqrt{3}+1}
Dividing by 1+\sqrt{3} undoes the multiplication by 1+\sqrt{3}.
r=6\sqrt{3}-6
Divide 12 by 1+\sqrt{3}.
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