Solve r+Fsqrt{3}=12

$$r + F \sqrt { 3 } = 12$$

Solve for F

$$F=-\frac{\sqrt{3}\left(r-12\right)}{3}$$

Steps for Solving Linear Equation

Subtract r from both sides.

$$F\sqrt{3}=12-r$$

The equation is in standard form.

$$\sqrt{3}F=12-r$$

Divide both sides by \sqrt{3}.

$$\frac{\sqrt{3}F}{\sqrt{3}}=\frac{12-r}{\sqrt{3}}$$

Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.

$$F=\frac{12-r}{\sqrt{3}}$$

Divide 12-r by \sqrt{3}.

$$F=\frac{\sqrt{3}\left(12-r\right)}{3}$$

Solve for r

$$r=-\sqrt{3}F+12$$

Solution Steps

Subtract F\sqrt{3} from both sides.

$$r=12-F\sqrt{3}$$

Reorder the terms.

$$r=-\sqrt{3}F+12$$