Solve q^2=118

$$q ^ { 2 } = 118$$

Solve for q

$$q=\sqrt{118}\approx 10.862780491$$

$$q=-\sqrt{118}\approx -10.862780491$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$q=\sqrt{118} q=-\sqrt{118}$$

Steps Using the Quadratic Formula

Subtract 118 from both sides.

$$q^{2}-118=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -118 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$q=\frac{0±\sqrt{0^{2}-4\left(-118\right)}}{2}$$

Square 0.

$$q=\frac{0±\sqrt{-4\left(-118\right)}}{2}$$

Multiply -4 times -118.

$$q=\frac{0±\sqrt{472}}{2}$$

Take the square root of 472.

$$q=\frac{0±2\sqrt{118}}{2}$$

Now solve the equation q=\frac{0±2\sqrt{118}}{2} when ± is plus.

$$q=\sqrt{118}$$

Now solve the equation q=\frac{0±2\sqrt{118}}{2} when ± is minus.

$$q=-\sqrt{118}$$

The equation is now solved.

$$q=\sqrt{118} q=-\sqrt{118}$$