Solve for a
a=-\frac{2q}{3}
Solve for q
q=-\frac{3a}{2}
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q=\left(-\frac{2+1}{2}\right)a
Multiply 1 and 2 to get 2.
q=-\frac{3}{2}a
Add 2 and 1 to get 3.
-\frac{3}{2}a=q
Swap sides so that all variable terms are on the left hand side.
\frac{-\frac{3}{2}a}{-\frac{3}{2}}=\frac{q}{-\frac{3}{2}}
Divide both sides of the equation by -\frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
a=\frac{q}{-\frac{3}{2}}
Dividing by -\frac{3}{2} undoes the multiplication by -\frac{3}{2}.
a=-\frac{2q}{3}
Divide q by -\frac{3}{2} by multiplying q by the reciprocal of -\frac{3}{2}.
q=\left(-\frac{2+1}{2}\right)a
Multiply 1 and 2 to get 2.
q=-\frac{3}{2}a
Add 2 and 1 to get 3.
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Limits
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