Solve px^2+30x+25=0m

$$p x ^ { 2 } + 30 x + 25 = 0 m$$

Solve for p

$$p=-\frac{5\left(6x+5\right)}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Anything times zero gives zero.

$$px^{2}+30x+25=0$$

Subtract 30x from both sides. Anything subtracted from zero gives its negation.

$$px^{2}+25=-30x$$

Subtract 25 from both sides.

$$px^{2}=-30x-25$$

The equation is in standard form.

$$x^{2}p=-30x-25$$

Divide both sides by x^{2}.

$$\frac{x^{2}p}{x^{2}}=\frac{-30x-25}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$p=\frac{-30x-25}{x^{2}}$$

Divide -25-30x by x^{2}.

$$p=-\frac{5\left(6x+5\right)}{x^{2}}$$

Solve for m (complex solution)

$$m\in \mathrm{C}$$

$$p=-\frac{5\left(6x+5\right)}{x^{2}}\text{ and }x\neq 0$$

Solve for m

$$m\in \mathrm{R}$$

$$p=-\frac{5\left(6x+5\right)}{x^{2}}\text{ and }x\neq 0$$