Solve p-q=pqqq

$$p - q = p q q q$$

Solve for p

$$p=\frac{q}{1-q^{3}}$$

$$q\neq 1$$

Steps for Solving Linear Equation

Multiply q and q to get q^{2}.

$$p-q=pq^{2}q$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$p-q=pq^{3}$$

Subtract pq^{3} from both sides.

$$p-q-pq^{3}=0$$

Add q to both sides. Anything plus zero gives itself.

$$p-pq^{3}=q$$

Combine all terms containing p.

$$\left(1-q^{3}\right)p=q$$

Divide both sides by 1-q^{3}.

$$\frac{\left(1-q^{3}\right)p}{1-q^{3}}=\frac{q}{1-q^{3}}$$

Dividing by 1-q^{3} undoes the multiplication by 1-q^{3}.

$$p=\frac{q}{1-q^{3}}$$

Divide q by 1-q^{3}.

$$p=\frac{q}{\left(1-q\right)\left(q^{2}+q+1\right)}$$