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Solve for q
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q\sqrt{3}+7=p-2\sqrt{3}
Swap sides so that all variable terms are on the left hand side.
q\sqrt{3}=p-2\sqrt{3}-7
Subtract 7 from both sides.
\sqrt{3}q=p-2\sqrt{3}-7
The equation is in standard form.
\frac{\sqrt{3}q}{\sqrt{3}}=\frac{p-2\sqrt{3}-7}{\sqrt{3}}
Divide both sides by \sqrt{3}.
q=\frac{p-2\sqrt{3}-7}{\sqrt{3}}
Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.
q=\frac{\sqrt{3}\left(p-2\sqrt{3}-7\right)}{3}
Divide p-2\sqrt{3}-7 by \sqrt{3}.