Factor
\left(p^{2}-8\right)\left(p^{4}+8p^{2}+64\right)
Evaluate
p^{6}-512
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\left(p^{2}-8\right)\left(p^{4}+8p^{2}+64\right)
Rewrite p^{6}-512 as \left(p^{2}\right)^{3}-8^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). The following polynomials are not factored since they do not have any rational roots: p^{2}-8,p^{4}+8p^{2}+64.
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