Solve p^2m+p^2n^5+qm+qn^5

$$p ^ { 2 } m + p ^ { 2 } n ^ { 5 } + q m + q n ^ { 5 }$$

Factor

$$\left(p^{2}+q\right)\left(m+n^{5}\right)$$

Solution Steps

Do the grouping p^{2}m+p^{2}n^{5}+qm+qn^{5}=\left(p^{2}m+p^{2}n^{5}\right)+\left(qm+qn^{5}\right), and factor out p^{2} in the first and q in the second group.

$$p^{2}\left(m+n^{5}\right)+q\left(m+n^{5}\right)$$

Factor out common term m+n^{5} by using distributive property.

$$\left(m+n^{5}\right)\left(p^{2}+q\right)$$

Evaluate

$$\left(p^{2}+q\right)\left(m+n^{5}\right)$$