Solve p^2-20k+25=0

$$p ^ { 2 } - 20 k + 25 = 0$$

Solve for k

$$k=\frac{p^{2}+25}{20}$$

Steps for Solving Linear Equation

Subtract p^{2} from both sides. Anything subtracted from zero gives its negation.

$$-20k+25=-p^{2}$$

Subtract 25 from both sides.

$$-20k=-p^{2}-25$$

Divide both sides by -20.

$$\frac{-20k}{-20}=\frac{-p^{2}-25}{-20}$$

Dividing by -20 undoes the multiplication by -20.

$$k=\frac{-p^{2}-25}{-20}$$

Divide -p^{2}-25 by -20.

$$k=\frac{p^{2}}{20}+\frac{5}{4}$$

Solve for p

$$p=\sqrt{20k-25}$$

$$p=-\sqrt{20k-25}\text{, }k\geq \frac{5}{4}$$