Solve p^2=-4

$$p ^ { 2 } = - 4$$

Solve for p

$$p=-2i$$

$$p=2i$$

Steps by Finding Square Root

The equation is now solved.

$$p=2i p=-2i$$

Steps Using the Quadratic Formula

Add 4 to both sides.

$$p^{2}+4=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$p=\frac{0±\sqrt{0^{2}-4\times 4}}{2}$$

Square 0.

$$p=\frac{0±\sqrt{-4\times 4}}{2}$$

Multiply -4 times 4.

$$p=\frac{0±\sqrt{-16}}{2}$$

Take the square root of -16.

$$p=\frac{0±4i}{2}$$

Now solve the equation p=\frac{0±4i}{2} when ± is plus.

$$p=2i$$

Now solve the equation p=\frac{0±4i}{2} when ± is minus.

$$p=-2i$$

The equation is now solved.

$$p=2i p=-2i$$