Solve otθ=2/sqrt{5}.text{Giventhat}θ

$$o t \theta = \frac { 2 } { \sqrt { 5 } } . \text { Given that } \theta$$

Solve for o

$$o=\frac{2\sqrt{5}}{5t\theta }$$

$$\theta \neq 0\text{ and }t\neq 0$$

Steps for Solving Linear Equation

Rationalize the denominator of \frac{2}{\sqrt{5}} by multiplying numerator and denominator by \sqrt{5}.

$$ot\theta =\frac{2\sqrt{5}}{\left(\sqrt{5}\right)^{2}}$$

The square of \sqrt{5} is 5.

$$ot\theta =\frac{2\sqrt{5}}{5}$$

Multiply both sides of the equation by 5.

$$5ot\theta =2\sqrt{5}$$

The equation is in standard form.

$$5t\theta o=2\sqrt{5}$$

Divide both sides by 5t\theta .

$$\frac{5t\theta o}{5t\theta }=\frac{2\sqrt{5}}{5t\theta }$$

Dividing by 5t\theta undoes the multiplication by 5t\theta .

$$o=\frac{2\sqrt{5}}{5t\theta }$$

Solve for t

$$t=\frac{2\sqrt{5}}{5o\theta }$$

$$\theta \neq 0\text{ and }o\neq 0$$

Steps for Solving Linear Equation

Rationalize the denominator of \frac{2}{\sqrt{5}} by multiplying numerator and denominator by \sqrt{5}.

$$ot\theta =\frac{2\sqrt{5}}{\left(\sqrt{5}\right)^{2}}$$

The square of \sqrt{5} is 5.

$$ot\theta =\frac{2\sqrt{5}}{5}$$

Multiply both sides of the equation by 5.

$$5ot\theta =2\sqrt{5}$$

The equation is in standard form.

$$5o\theta t=2\sqrt{5}$$

Divide both sides by 5o\theta .

$$\frac{5o\theta t}{5o\theta }=\frac{2\sqrt{5}}{5o\theta }$$

Dividing by 5o\theta undoes the multiplication by 5o\theta .

$$t=\frac{2\sqrt{5}}{5o\theta }$$