Solve nx+(n-1)=38

$$n x + ( n - 1 ) = 38$$

Solve for n

$$n=\frac{39}{x+1}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Add 1 to both sides.

$$nx+n=38+1$$

Add 38 and 1 to get 39.

$$nx+n=39$$

Combine all terms containing n.

$$\left(x+1\right)n=39$$

Divide both sides by x+1.

$$\frac{\left(x+1\right)n}{x+1}=\frac{39}{x+1}$$

Dividing by x+1 undoes the multiplication by x+1.

$$n=\frac{39}{x+1}$$

Solve for x

$$x=-1+\frac{39}{n}$$

$$n\neq 0$$

Steps for Solving Linear Equation

Subtract n from both sides.

$$nx-1=38-n$$

Add 1 to both sides.

$$nx=38-n+1$$

Add 38 and 1 to get 39.

$$nx=39-n$$

Divide both sides by n.

$$\frac{nx}{n}=\frac{39-n}{n}$$

Dividing by n undoes the multiplication by n.

$$x=\frac{39-n}{n}$$

Divide 39-n by n.

$$x=-1+\frac{39}{n}$$