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n\times \frac{8}{27}<n\times \left(\frac{1}{2}\right)^{2}
Calculate \frac{2}{3} to the power of 3 and get \frac{8}{27}.
n\times \frac{8}{27}<n\times \frac{1}{4}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
n\times \frac{8}{27}-n\times \frac{1}{4}<0
Subtract n\times \frac{1}{4} from both sides.
\frac{5}{108}n<0
Combine n\times \frac{8}{27} and -n\times \frac{1}{4} to get \frac{5}{108}n.
n<0
Product of two numbers is <0 if one is >0 and the other is <0. Since \frac{5}{108}>0, n must be <0.