Solve for n
n=\frac{3}{5\theta }
\theta \neq 0
Solve for θ
\theta =\frac{3}{5n}
n\neq 0
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\theta n=\frac{3}{5}
The equation is in standard form.
\frac{\theta n}{\theta }=\frac{\frac{3}{5}}{\theta }
Divide both sides by \theta .
n=\frac{\frac{3}{5}}{\theta }
Dividing by \theta undoes the multiplication by \theta .
n=\frac{3}{5\theta }
Divide \frac{3}{5} by \theta .
n\theta =\frac{3}{5}
The equation is in standard form.
\frac{n\theta }{n}=\frac{\frac{3}{5}}{n}
Divide both sides by n.
\theta =\frac{\frac{3}{5}}{n}
Dividing by n undoes the multiplication by n.
\theta =\frac{3}{5n}
Divide \frac{3}{5} by n.
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