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n^{2}\left(n-5\right)-4\left(n-5\right)
Do the grouping n^{3}-5n^{2}-4n+20=\left(n^{3}-5n^{2}\right)+\left(-4n+20\right), and factor out n^{2} in the first and -4 in the second group.
\left(n-5\right)\left(n^{2}-4\right)
Factor out common term n-5 by using distributive property.
\left(n-2\right)\left(n+2\right)
Consider n^{2}-4. Rewrite n^{2}-4 as n^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(n-5\right)\left(n-2\right)\left(n+2\right)
Rewrite the complete factored expression.