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n^{2}=5
Add 5 to both sides. Anything plus zero gives itself.
n=\sqrt{5} n=-\sqrt{5}
Take the square root of both sides of the equation.
n^{2}-5=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
n=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{0±\sqrt{-4\left(-5\right)}}{2}
Square 0.
n=\frac{0±\sqrt{20}}{2}
Multiply -4 times -5.
n=\frac{0±2\sqrt{5}}{2}
Take the square root of 20.
n=\sqrt{5}
Now solve the equation n=\frac{0±2\sqrt{5}}{2} when ± is plus.
n=-\sqrt{5}
Now solve the equation n=\frac{0±2\sqrt{5}}{2} when ± is minus.
n=\sqrt{5} n=-\sqrt{5}
The equation is now solved.