Solve n^2-20n^2+64

$$n ^ { 2 } - 20 n ^ { 2 } + 64$$

Differentiate w.r.t. n

$$-38n$$

Steps Using Derivative Rule for Sum

Combine n^{2} and -20n^{2} to get -19n^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-19n^{2}+64)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\left(-19\right)n^{2-1}$$

Multiply 2 times -19.

$$-38n^{2-1}$$

Subtract 1 from 2.

$$-38n^{1}$$

For any term t, t^{1}=t.

$$-38n$$

Evaluate

$$64-19n^{2}$$

Solution Steps

Combine n^{2} and -20n^{2} to get -19n^{2}.

$$-19n^{2}+64$$