Solve for m
m=-1+\frac{8}{x}
x\neq 0
Solve for x
x=\frac{8}{m+1}
m\neq -1
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mx=8-x
Subtract x from both sides.
xm=8-x
The equation is in standard form.
\frac{xm}{x}=\frac{8-x}{x}
Divide both sides by x.
m=\frac{8-x}{x}
Dividing by x undoes the multiplication by x.
m=-1+\frac{8}{x}
Divide 8-x by x.
\left(m+1\right)x=8
Combine all terms containing x.
\frac{\left(m+1\right)x}{m+1}=\frac{8}{m+1}
Divide both sides by m+1.
x=\frac{8}{m+1}
Dividing by m+1 undoes the multiplication by m+1.
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