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t^{2}+13t+36=0
Substitute t for m^{2}.
t=\frac{-13±\sqrt{13^{2}-4\times 1\times 36}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 13 for b, and 36 for c in the quadratic formula.
t=\frac{-13±5}{2}
Do the calculations.
t=-4 t=-9
Solve the equation t=\frac{-13±5}{2} when ± is plus and when ± is minus.
m=-2i m=2i m=-3i m=3i
Since m=t^{2}, the solutions are obtained by evaluating m=±\sqrt{t} for each t.