Solve m^2-4sigmam-56=0

$$m ^ { 2 } - 4 \sigma m - 56 = 0$$

Solve for σ

$$\sigma =\frac{m}{4}-\frac{14}{m}$$

$$m\neq 0$$

Steps for Solving Linear Equation

Subtract m^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4\sigma m-56=-m^{2}$$

Add 56 to both sides.

$$-4\sigma m=-m^{2}+56$$

The equation is in standard form.

$$\left(-4m\right)\sigma =56-m^{2}$$

Divide both sides by -4m.

$$\frac{\left(-4m\right)\sigma }{-4m}=\frac{56-m^{2}}{-4m}$$

Dividing by -4m undoes the multiplication by -4m.

$$\sigma =\frac{56-m^{2}}{-4m}$$

Divide -m^{2}+56 by -4m.

$$\sigma =\frac{m}{4}-\frac{14}{m}$$

Solve for m

$$m=2\left(\sqrt{\sigma ^{2}+14}+\sigma \right)$$

$$m=2\left(-\sqrt{\sigma ^{2}+14}+\sigma \right)$$