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m^{2}+2m=7
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
m^{2}+2m-7=7-7
Subtract 7 from both sides of the equation.
m^{2}+2m-7=0
Subtracting 7 from itself leaves 0.
m=\frac{-2±\sqrt{2^{2}-4\left(-7\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 2 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-2±\sqrt{4-4\left(-7\right)}}{2}
Square 2.
m=\frac{-2±\sqrt{4+28}}{2}
Multiply -4 times -7.
m=\frac{-2±\sqrt{32}}{2}
Add 4 to 28.
m=\frac{-2±4\sqrt{2}}{2}
Take the square root of 32.
m=\frac{4\sqrt{2}-2}{2}
Now solve the equation m=\frac{-2±4\sqrt{2}}{2} when ± is plus. Add -2 to 4\sqrt{2}.
m=2\sqrt{2}-1
Divide 4\sqrt{2}-2 by 2.
m=\frac{-4\sqrt{2}-2}{2}
Now solve the equation m=\frac{-2±4\sqrt{2}}{2} when ± is minus. Subtract 4\sqrt{2} from -2.
m=-2\sqrt{2}-1
Divide -2-4\sqrt{2} by 2.
m=2\sqrt{2}-1 m=-2\sqrt{2}-1
The equation is now solved.
m^{2}+2m=7
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
m^{2}+2m+1^{2}=7+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
m^{2}+2m+1=7+1
Square 1.
m^{2}+2m+1=8
Add 7 to 1.
\left(m+1\right)^{2}=8
Factor m^{2}+2m+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m+1\right)^{2}}=\sqrt{8}
Take the square root of both sides of the equation.
m+1=2\sqrt{2} m+1=-2\sqrt{2}
Simplify.
m=2\sqrt{2}-1 m=-2\sqrt{2}-1
Subtract 1 from both sides of the equation.