Solve for m
m=\frac{461}{483}\approx 0.954451346
Assign m
m≔\frac{461}{483}
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m=\frac{230}{483}+\frac{231}{483}
Least common multiple of 21 and 23 is 483. Convert \frac{10}{21} and \frac{11}{23} to fractions with denominator 483.
m=\frac{230+231}{483}
Since \frac{230}{483} and \frac{231}{483} have the same denominator, add them by adding their numerators.
m=\frac{461}{483}
Add 230 and 231 to get 461.
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