Solve m+1+n=mn

$$m + 1 + n = m n$$

Solve for m

$$m=-\frac{n+1}{1-n}$$

$$n\neq 1$$

Steps for Solving Linear Equation

Subtract mn from both sides.

$$m+1+n-mn=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$m+n-mn=-1$$

Subtract n from both sides.

$$m-mn=-1-n$$

Combine all terms containing m.

$$\left(1-n\right)m=-1-n$$

The equation is in standard form.

$$\left(1-n\right)m=-n-1$$

Divide both sides by 1-n.

$$\frac{\left(1-n\right)m}{1-n}=\frac{-n-1}{1-n}$$

Dividing by 1-n undoes the multiplication by 1-n.

$$m=\frac{-n-1}{1-n}$$

Divide -1-n by 1-n.

$$m=-\frac{n+1}{1-n}$$

Solve for n

$$n=-\frac{m+1}{1-m}$$

$$m\neq 1$$

Steps for Solving Linear Equation

Subtract mn from both sides.

$$m+1+n-mn=0$$

Subtract m from both sides. Anything subtracted from zero gives its negation.

$$1+n-mn=-m$$

Subtract 1 from both sides.

$$n-mn=-m-1$$

Combine all terms containing n.

$$\left(1-m\right)n=-m-1$$

Divide both sides by 1-m.

$$\frac{\left(1-m\right)n}{1-m}=\frac{-m-1}{1-m}$$

Dividing by 1-m undoes the multiplication by 1-m.

$$n=\frac{-m-1}{1-m}$$

Divide -m-1 by 1-m.

$$n=-\frac{m+1}{1-m}$$