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k=\sqrt{3} k=-\sqrt{3}
Take the square root of both sides of the equation.
k^{2}-3=0
Subtract 3 from both sides.
k=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
k=\frac{0±\sqrt{-4\left(-3\right)}}{2}
Square 0.
k=\frac{0±\sqrt{12}}{2}
Multiply -4 times -3.
k=\frac{0±2\sqrt{3}}{2}
Take the square root of 12.
k=\sqrt{3}
Now solve the equation k=\frac{0±2\sqrt{3}}{2} when ± is plus.
k=-\sqrt{3}
Now solve the equation k=\frac{0±2\sqrt{3}}{2} when ± is minus.
k=\sqrt{3} k=-\sqrt{3}
The equation is now solved.