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k^{2}=576
Multiply 16 and 36 to get 576.
k^{2}-576=0
Subtract 576 from both sides.
\left(k-24\right)\left(k+24\right)=0
Consider k^{2}-576. Rewrite k^{2}-576 as k^{2}-24^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
k=24 k=-24
To find equation solutions, solve k-24=0 and k+24=0.
k^{2}=576
Multiply 16 and 36 to get 576.
k=24 k=-24
Take the square root of both sides of the equation.
k^{2}=576
Multiply 16 and 36 to get 576.
k^{2}-576=0
Subtract 576 from both sides.
k=\frac{0±\sqrt{0^{2}-4\left(-576\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -576 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
k=\frac{0±\sqrt{-4\left(-576\right)}}{2}
Square 0.
k=\frac{0±\sqrt{2304}}{2}
Multiply -4 times -576.
k=\frac{0±48}{2}
Take the square root of 2304.
k=24
Now solve the equation k=\frac{0±48}{2} when ± is plus. Divide 48 by 2.
k=-24
Now solve the equation k=\frac{0±48}{2} when ± is minus. Divide -48 by 2.
k=24 k=-24
The equation is now solved.