Solve for y
\left\{\begin{matrix}y=\frac{k}{2z}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&k=0\text{ and }z=0\end{matrix}\right.
Solve for k
k=2yz
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2yz=k
Swap sides so that all variable terms are on the left hand side.
2zy=k
The equation is in standard form.
\frac{2zy}{2z}=\frac{k}{2z}
Divide both sides by 2z.
y=\frac{k}{2z}
Dividing by 2z undoes the multiplication by 2z.
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