Solve j^2+98j-a=0

$$j ^ { 2 } + 98 j - a = 0$$

Solve for a

$$a=j\left(j+98\right)$$

Steps for Solving Linear Equation

Subtract j^{2} from both sides. Anything subtracted from zero gives its negation.

$$98j-a=-j^{2}$$

Subtract 98j from both sides.

$$-a=-j^{2}-98j$$

Divide both sides by -1.

$$\frac{-a}{-1}=-\frac{j\left(j+98\right)}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$a=-\frac{j\left(j+98\right)}{-1}$$

Divide -j\left(98+j\right) by -1.

$$a=j\left(j+98\right)$$

Solve for j (complex solution)

$$j=\sqrt{a+2401}-49$$

$$j=-\sqrt{a+2401}-49$$

Solve for j

$$j=\sqrt{a+2401}-49$$

$$j=-\sqrt{a+2401}-49\text{, }a\geq -2401$$