Solve i+37sqrt{(-3)^2}-(sqrt{3})^2=

$$i + 37 \sqrt { ( - 3 ) ^ { 2 } } - ( \sqrt { 3 } ) ^ { 2 } =$$

Evaluate

$$108+i$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$i+37\sqrt{9}-\left(\sqrt{3}\right)^{2}$$

Calculate the square root of 9 and get 3.

$$i+37\times 3-\left(\sqrt{3}\right)^{2}$$

Multiply 37 and 3 to get 111.

$$i+111-\left(\sqrt{3}\right)^{2}$$

The square of \sqrt{3} is 3.

$$i+111-3$$

Do the additions.

$$108+i$$

Real Part

$$108$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$Re(i+37\sqrt{9}-\left(\sqrt{3}\right)^{2})$$

Calculate the square root of 9 and get 3.

$$Re(i+37\times 3-\left(\sqrt{3}\right)^{2})$$

Multiply 37 and 3 to get 111.

$$Re(i+111-\left(\sqrt{3}\right)^{2})$$

The square of \sqrt{3} is 3.

$$Re(i+111-3)$$

Do the additions in i+111-3.

$$Re(108+i)$$

The real part of 108+i is 108.

$$108$$