Solve h(x)=2/x+3-2

$$h ( x ) = \frac { 2 } { x + 3 } - 2$$

Evaluate

$$-\frac{2\left(x+2\right)}{x+3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{x+3}{x+3}.

$$\frac{2}{x+3}-\frac{2\left(x+3\right)}{x+3}$$

Since \frac{2}{x+3} and \frac{2\left(x+3\right)}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-2\left(x+3\right)}{x+3}$$

Do the multiplications in 2-2\left(x+3\right).

$$\frac{2-2x-6}{x+3}$$

Combine like terms in 2-2x-6.

$$\frac{-4-2x}{x+3}$$

Factor

$$-\frac{2\left(x+2\right)}{x+3}$$