Solve h(t)=3*4^ttext{for}t=-3

$$h ( t ) = 3 \cdot 4 ^ { t } \text { for } t = - 3$$

Solve for h, t

$$t=-3$$

$$h=-\frac{1}{64}=-0.015625$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$h\left(-3\right)=3\times 4^{-3}$$

Calculate 4 to the power of -3 and get \frac{1}{64}.

$$h\left(-3\right)=3\times \frac{1}{64}$$

Multiply 3 and \frac{1}{64} to get \frac{3}{64}.

$$h\left(-3\right)=\frac{3}{64}$$

Divide both sides by -3.

$$h=\frac{\frac{3}{64}}{-3}$$

Express \frac{\frac{3}{64}}{-3} as a single fraction.

$$h=\frac{3}{64\left(-3\right)}$$

Multiply 64 and -3 to get -192.

$$h=\frac{3}{-192}$$

Reduce the fraction \frac{3}{-192} to lowest terms by extracting and canceling out 3.

$$h=-\frac{1}{64}$$

The system is now solved.

$$h=-\frac{1}{64} t=-3$$