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\frac{-x^{2}+4x+12}{4}
Factor out \frac{1}{4}.
a+b=4 ab=-12=-12
Consider -x^{2}+4x+12. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+12. To find a and b, set up a system to be solved.
-1,12 -2,6 -3,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -12.
-1+12=11 -2+6=4 -3+4=1
Calculate the sum for each pair.
a=6 b=-2
The solution is the pair that gives sum 4.
\left(-x^{2}+6x\right)+\left(-2x+12\right)
Rewrite -x^{2}+4x+12 as \left(-x^{2}+6x\right)+\left(-2x+12\right).
-x\left(x-6\right)-2\left(x-6\right)
Factor out -x in the first and -2 in the second group.
\left(x-6\right)\left(-x-2\right)
Factor out common term x-6 by using distributive property.
\frac{\left(x-6\right)\left(-x-2\right)}{4}
Rewrite the complete factored expression.