Solve for d
d=2g-f
Solve for f
f=2g-d
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g=\frac{1}{2}d+\frac{1}{2}f
Divide each term of d+f by 2 to get \frac{1}{2}d+\frac{1}{2}f.
\frac{1}{2}d+\frac{1}{2}f=g
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}d=g-\frac{1}{2}f
Subtract \frac{1}{2}f from both sides.
\frac{1}{2}d=-\frac{f}{2}+g
The equation is in standard form.
\frac{\frac{1}{2}d}{\frac{1}{2}}=\frac{-\frac{f}{2}+g}{\frac{1}{2}}
Multiply both sides by 2.
d=\frac{-\frac{f}{2}+g}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
d=2g-f
Divide g-\frac{f}{2} by \frac{1}{2} by multiplying g-\frac{f}{2} by the reciprocal of \frac{1}{2}.
g=\frac{1}{2}d+\frac{1}{2}f
Divide each term of d+f by 2 to get \frac{1}{2}d+\frac{1}{2}f.
\frac{1}{2}d+\frac{1}{2}f=g
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}f=g-\frac{1}{2}d
Subtract \frac{1}{2}d from both sides.
\frac{1}{2}f=-\frac{d}{2}+g
The equation is in standard form.
\frac{\frac{1}{2}f}{\frac{1}{2}}=\frac{-\frac{d}{2}+g}{\frac{1}{2}}
Multiply both sides by 2.
f=\frac{-\frac{d}{2}+g}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
f=2g-d
Divide g-\frac{d}{2} by \frac{1}{2} by multiplying g-\frac{d}{2} by the reciprocal of \frac{1}{2}.
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Limits
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