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Solve for f
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Solve for g
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g=\frac{5}{3}e+\frac{4}{3}f
Divide each term of 5e+4f by 3 to get \frac{5}{3}e+\frac{4}{3}f.
\frac{5}{3}e+\frac{4}{3}f=g
Swap sides so that all variable terms are on the left hand side.
\frac{4}{3}f=g-\frac{5}{3}e
Subtract \frac{5}{3}e from both sides.
\frac{4}{3}f=g-\frac{5e}{3}
The equation is in standard form.
\frac{\frac{4}{3}f}{\frac{4}{3}}=\frac{g-\frac{5e}{3}}{\frac{4}{3}}
Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
f=\frac{g-\frac{5e}{3}}{\frac{4}{3}}
Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.
f=\frac{3g-5e}{4}
Divide g-\frac{5e}{3} by \frac{4}{3} by multiplying g-\frac{5e}{3} by the reciprocal of \frac{4}{3}.
g=\frac{5}{3}e+\frac{4}{3}f
Divide each term of 5e+4f by 3 to get \frac{5}{3}e+\frac{4}{3}f.