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\frac{4x^{2}-4ax-3a^{2}}{4}
Factor out \frac{1}{4}.
\left(2x-3a\right)\left(2x+a\right)
Consider 4x^{2}-4ax-3a^{2}. Consider 4x^{2}-4ax-3a^{2} as a polynomial over variable x. Find one factor of the form kx^{m}+n, where kx^{m} divides the monomial with the highest power 4x^{2} and n divides the constant factor -3a^{2}. One such factor is 2x-3a. Factor the polynomial by dividing it by this factor.
\frac{\left(2x-3a\right)\left(2x+a\right)}{4}
Rewrite the complete factored expression.