Solve for f
f=\frac{3x+25}{2}
Solve for x
x=\frac{2f-25}{3}
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2f-20=3x+5
Multiply both sides of the equation by 2.
2f=3x+5+20
Add 20 to both sides.
2f=3x+25
Add 5 and 20 to get 25.
\frac{2f}{2}=\frac{3x+25}{2}
Divide both sides by 2.
f=\frac{3x+25}{2}
Dividing by 2 undoes the multiplication by 2.
2f-20=3x+5
Multiply both sides of the equation by 2.
3x+5=2f-20
Swap sides so that all variable terms are on the left hand side.
3x=2f-20-5
Subtract 5 from both sides.
3x=2f-25
Subtract 5 from -20 to get -25.
\frac{3x}{3}=\frac{2f-25}{3}
Divide both sides by 3.
x=\frac{2f-25}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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