Solve for t (complex solution)
\left\{\begin{matrix}t=\frac{f}{2\left(x+1\right)e^{x}}\text{, }&x\neq -1\\t\in \mathrm{C}\text{, }&f=0\text{ and }x=-1\end{matrix}\right.
Solve for t
\left\{\begin{matrix}t=\frac{f}{2\left(x+1\right)e^{x}}\text{, }&x\neq -1\\t\in \mathrm{R}\text{, }&f=0\text{ and }x=-1\end{matrix}\right.
Solve for f
f=2t\left(x+1\right)e^{x}
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f\frac{\mathrm{d}}{\mathrm{d}x}(x)=2te^{x}x+2te^{x}
Use the distributive property to multiply 2te^{x} by x+1.
2te^{x}x+2te^{x}=f\frac{\mathrm{d}}{\mathrm{d}x}(x)
Swap sides so that all variable terms are on the left hand side.
\left(2e^{x}x+2e^{x}\right)t=f\frac{\mathrm{d}}{\mathrm{d}x}(x)
Combine all terms containing t.
\left(2xe^{x}+2e^{x}\right)t=f
The equation is in standard form.
\frac{\left(2xe^{x}+2e^{x}\right)t}{2xe^{x}+2e^{x}}=\frac{f}{2xe^{x}+2e^{x}}
Divide both sides by 2e^{x}x+2e^{x}.
t=\frac{f}{2xe^{x}+2e^{x}}
Dividing by 2e^{x}x+2e^{x} undoes the multiplication by 2e^{x}x+2e^{x}.
t=\frac{f}{2\left(x+1\right)e^{x}}
Divide f by 2e^{x}x+2e^{x}.
f\frac{\mathrm{d}}{\mathrm{d}x}(x)=2te^{x}x+2te^{x}
Use the distributive property to multiply 2te^{x} by x+1.
2te^{x}x+2te^{x}=f\frac{\mathrm{d}}{\mathrm{d}x}(x)
Swap sides so that all variable terms are on the left hand side.
\left(2e^{x}x+2e^{x}\right)t=f\frac{\mathrm{d}}{\mathrm{d}x}(x)
Combine all terms containing t.
\left(2xe^{x}+2e^{x}\right)t=f
The equation is in standard form.
\frac{\left(2xe^{x}+2e^{x}\right)t}{2xe^{x}+2e^{x}}=\frac{f}{2xe^{x}+2e^{x}}
Divide both sides by 2e^{x}x+2e^{x}.
t=\frac{f}{2xe^{x}+2e^{x}}
Dividing by 2e^{x}x+2e^{x} undoes the multiplication by 2e^{x}x+2e^{x}.
t=\frac{f}{2\left(x+1\right)e^{x}}
Divide f by 2e^{x}x+2e^{x}.
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