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5x^{4}+80x^{3}+276x^{2}+16x+55=0
To factor the expression, solve the equation where it equals to 0.
±11,±55,±\frac{11}{5},±1,±5,±\frac{1}{5}
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 55 and q divides the leading coefficient 5. List all candidates \frac{p}{q}.
x=-5
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
5x^{3}+55x^{2}+x+11=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 5x^{4}+80x^{3}+276x^{2}+16x+55 by x+5 to get 5x^{3}+55x^{2}+x+11. To factor the result, solve the equation where it equals to 0.
±\frac{11}{5},±11,±\frac{1}{5},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 11 and q divides the leading coefficient 5. List all candidates \frac{p}{q}.
x=-11
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
5x^{2}+1=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 5x^{3}+55x^{2}+x+11 by x+11 to get 5x^{2}+1. To factor the result, solve the equation where it equals to 0.
x=\frac{0±\sqrt{0^{2}-4\times 5\times 1}}{2\times 5}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 5 for a, 0 for b, and 1 for c in the quadratic formula.
x=\frac{0±\sqrt{-20}}{10}
Do the calculations.
5x^{2}+1
Polynomial 5x^{2}+1 is not factored since it does not have any rational roots.
\left(x+5\right)\left(x+11\right)\left(5x^{2}+1\right)
Rewrite the factored expression using the obtained roots.