Solve f(x)=1-2xquadg(x)=x+4quadh(x)=

$$f ( x ) = 1 - 2 x \quad g ( x ) = x + 4 \quad h ( x ) =$$

Solve for g

$$g=\frac{1-x-4hx}{2x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$1-2x^{2}g=x+4hx$$

Subtract 1 from both sides.

$$-2x^{2}g=x+4hx-1$$

The equation is in standard form.

$$\left(-2x^{2}\right)g=4hx+x-1$$

Divide both sides by -2x^{2}.

$$\frac{\left(-2x^{2}\right)g}{-2x^{2}}=\frac{4hx+x-1}{-2x^{2}}$$

Dividing by -2x^{2} undoes the multiplication by -2x^{2}.

$$g=\frac{4hx+x-1}{-2x^{2}}$$

Divide x+4hx-1 by -2x^{2}.

$$g=-\frac{4hx+x-1}{2x^{2}}$$

Solve for h

$$h=-\frac{gx}{2}-\frac{1}{4}+\frac{1}{4x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$1-2x^{2}g=x+4hx$$

Swap sides so that all variable terms are on the left hand side.

$$x+4hx=1-2x^{2}g$$

Subtract x from both sides.

$$4hx=1-2x^{2}g-x$$

The equation is in standard form.

$$4xh=1-x-2gx^{2}$$

Divide both sides by 4x.

$$\frac{4xh}{4x}=\frac{1-x-2gx^{2}}{4x}$$

Dividing by 4x undoes the multiplication by 4x.

$$h=\frac{1-x-2gx^{2}}{4x}$$

Divide 1-2gx^{2}-x by 4x.

$$h=-\frac{gx}{2}-\frac{1}{4}+\frac{1}{4x}$$