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\left(x-5\right)\left(-x^{2}+10x-25\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 125 and q divides the leading coefficient -1. One such root is 5. Factor the polynomial by dividing it by x-5.
a+b=10 ab=-\left(-25\right)=25
Consider -x^{2}+10x-25. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx-25. To find a and b, set up a system to be solved.
1,25 5,5
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 25.
1+25=26 5+5=10
Calculate the sum for each pair.
a=5 b=5
The solution is the pair that gives sum 10.
\left(-x^{2}+5x\right)+\left(5x-25\right)
Rewrite -x^{2}+10x-25 as \left(-x^{2}+5x\right)+\left(5x-25\right).
-x\left(x-5\right)+5\left(x-5\right)
Factor out -x in the first and 5 in the second group.
\left(x-5\right)\left(-x+5\right)
Factor out common term x-5 by using distributive property.
\left(-x+5\right)\left(x-5\right)^{2}
Rewrite the complete factored expression.