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\frac{-2x^{2}+3x+2}{2}
Factor out \frac{1}{2}.
a+b=3 ab=-2\times 2=-4
Consider -2x^{2}+3x+2. Factor the expression by grouping. First, the expression needs to be rewritten as -2x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,4 -2,2
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -4.
-1+4=3 -2+2=0
Calculate the sum for each pair.
a=4 b=-1
The solution is the pair that gives sum 3.
\left(-2x^{2}+4x\right)+\left(-x+2\right)
Rewrite -2x^{2}+3x+2 as \left(-2x^{2}+4x\right)+\left(-x+2\right).
2x\left(-x+2\right)-x+2
Factor out 2x in -2x^{2}+4x.
\left(-x+2\right)\left(2x+1\right)
Factor out common term -x+2 by using distributive property.
\frac{\left(-x+2\right)\left(2x+1\right)}{2}
Rewrite the complete factored expression.