Solve for g
g=2x^{2}-4+\frac{5}{x}
x\neq 0
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-gx=-2x^{3}-5+4x
Add 4x to both sides.
\left(-x\right)g=-2x^{3}+4x-5
The equation is in standard form.
\frac{\left(-x\right)g}{-x}=\frac{-2x^{3}+4x-5}{-x}
Divide both sides by -x.
g=\frac{-2x^{3}+4x-5}{-x}
Dividing by -x undoes the multiplication by -x.
g=2x^{2}-4+\frac{5}{x}
Divide -2x^{3}-5+4x by -x.
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