f ( x ) = - 2 x ^ { 2 } + x \quad ( - 1,4 )
Solve for f
\left\{\begin{matrix}\\f=-2x-1,4\text{, }&\text{unconditionally}\\f\in \mathrm{R}\text{, }&x=0\end{matrix}\right.
Solve for x
x=-\frac{f}{2}-0,7
x=0
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xf=-2x^{2}-\frac{7x}{5}
The equation is in standard form.
\frac{xf}{x}=-\frac{x\left(2x+1,4\right)}{x}
Divide both sides by x.
f=-\frac{x\left(2x+1,4\right)}{x}
Dividing by x undoes the multiplication by x.
f=-2x-1,4
Divide -x\left(1,4+2x\right) by x.
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