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\frac{-x^{3}-3x^{2}+4}{2}
Factor out \frac{1}{2}.
\left(x+2\right)\left(-x^{2}-x+2\right)
Consider -x^{3}-3x^{2}+4. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 4 and q divides the leading coefficient -1. One such root is -2. Factor the polynomial by dividing it by x+2.
a+b=-1 ab=-2=-2
Consider -x^{2}-x+2. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
a=1 b=-2
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. The only such pair is the system solution.
\left(-x^{2}+x\right)+\left(-2x+2\right)
Rewrite -x^{2}-x+2 as \left(-x^{2}+x\right)+\left(-2x+2\right).
x\left(-x+1\right)+2\left(-x+1\right)
Factor out x in the first and 2 in the second group.
\left(-x+1\right)\left(x+2\right)
Factor out common term -x+1 by using distributive property.
\frac{\left(x+2\right)^{2}\left(-x+1\right)}{2}
Rewrite the complete factored expression.