Solve f(x)=(3^21)+1(2^2-2x-1)

$$f ( x ) = ( 3 ^ { 2 } 1 ) + 1 ( 2 ^ { 2 } - 2 x - 1 )$$

Evaluate

$$12-2x$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9\times 1+1\left(2^{2}-2x-1\right)$$

Multiply 9 and 1 to get 9.

$$9+1\left(2^{2}-2x-1\right)$$

Calculate 2 to the power of 2 and get 4.

$$9+1\left(4-2x-1\right)$$

Subtract 1 from 4 to get 3.

$$9+1\left(3-2x\right)$$

Use the distributive property to multiply 1 by 3-2x.

$$9+3-2x$$

Add 9 and 3 to get 12.

$$12-2x$$

Factor

$$2\left(6-x\right)$$

Solution Steps

Multiply and combine like terms.

$$-2x+12$$

Factor out 2.

$$2\left(-x+6\right)$$