f ( x ) = \frac { x ^ { 3 } - 1 } { }
Solve for f
f=\frac{x^{3}-1}{x}
x\neq 0
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fx=x^{3}-1
Anything divided by one gives itself.
xf=x^{3}-1
The equation is in standard form.
\frac{xf}{x}=\frac{x^{3}-1}{x}
Divide both sides by x.
f=\frac{x^{3}-1}{x}
Dividing by x undoes the multiplication by x.
f=x^{2}-\frac{1}{x}
Divide x^{3}-1 by x.
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