Solve f(x)=cos^3(5-4x^2)text{adalah}f^prime(x)

$$f ( x ) = \cos ^ { 3 } ( 5 - 4 x ^ { 2 } ) \text { adalah } f ^ { \prime } ( x )$$

Solve for d

$$d\in \mathrm{R}$$

$$f=0\text{ or }x=0$$

Steps for Solving Linear Equation

Multiply a and a to get a^{2}.

$$fx=\left(\cos(5-4x^{2})\right)^{3}a^{2}dlah\frac{\mathrm{d}}{\mathrm{d}x}(f)x$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$fx=\left(\cos(5-4x^{2})\right)^{3}a^{3}dlh\frac{\mathrm{d}}{\mathrm{d}x}(f)x$$

Swap sides so that all variable terms are on the left hand side.

$$\left(\cos(5-4x^{2})\right)^{3}a^{3}dlh\frac{\mathrm{d}}{\mathrm{d}x}(f)x=fx$$

The equation is in standard form.

$$0=fx$$

This is false for any d.

$$d\in$$

Solve for a

$$a\in \mathrm{R}$$

$$f=0\text{ or }x=0$$