Solve for f
f=5x^{2}+7-\frac{9}{x}
x\neq 0
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fx=7x+5x^{3}-9
Subtract 9 from both sides.
xf=5x^{3}+7x-9
The equation is in standard form.
\frac{xf}{x}=\frac{5x^{3}+7x-9}{x}
Divide both sides by x.
f=\frac{5x^{3}+7x-9}{x}
Dividing by x undoes the multiplication by x.
f=5x^{2}+7-\frac{9}{x}
Divide 7x+5x^{3}-9 by x.
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