Solve f(3)=2*3^3+4*3^2+10*3+1

$$f ( 3 ) = 2 \cdot 3 ^ { 3 } + 4 \cdot 3 ^ { 2 } + 10 \cdot 3 + 1$$

Evaluate

$$121$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$2\times 27+4\times 3^{2}+10\times 3+1$$

Multiply 2 and 27 to get 54.

$$54+4\times 3^{2}+10\times 3+1$$

Calculate 3 to the power of 2 and get 9.

$$54+4\times 9+10\times 3+1$$

Multiply 4 and 9 to get 36.

$$54+36+10\times 3+1$$

Add 54 and 36 to get 90.

$$90+10\times 3+1$$

Multiply 10 and 3 to get 30.

$$90+30+1$$

Add 90 and 30 to get 120.

$$120+1$$

Add 120 and 1 to get 121.

$$121$$

Factor

$$11^{2}$$